Page 130 - ebook fluid mechanics_finalize
P. 130
FLUID MECHANICS
Solution to Example 5.5
1 1
Q = d 2 v = d 2 v
4 1 1 4 2 2
v = 4Q 2 v = 4Q 2
1
2
d 2 d 1
4 8 . 2 10 − 3 4 8 . 2 10 − 3
= =
( 075.0 ) 2 ( 05.0 ) 2
0= . 634 m s /
Applying Bernoulli’s equation to A and B at which pA = pB = atmospheric pressure and vA =
0, for unit weight
Total energy at A = total energy at D + shock loss at B + frictional loss in BC
+ shock loss at C + frictional loss in CD
There is no shock loss at D as discharge is to atmosphere.
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