Page 38 - eEISBN FINALIZE
P. 38
ΣFxi = (519.61 – 282.84) i = 236.77 N i
ΣFyj = (300 – 282.84 )j = 582.84 Nj
FR = 236.77 i + 582.84 j
Magnitude FR
= √∑ + ∑
2
2
= √236.77 + 582.84
2
2
= 629
Direction θR
∑
= tan −1 [ ]
∑
582.84
= tan −1 [ ]
236.77
= 67.9
0
29
