Page 74 - eEISBN FINALIZE

iii. Total distance traveled : = + +

1
= ( + )
2
1
= (0 + 160)10
2

=

1
= ( + )

2
1
= (160 + 280)15

2
=

1
= ( + )

2
1
= (280 + 0)15

2
=

Hence:

= + +

= 800 + 3300 + 2100

=

Example 4

-1
-2
A particle has an initial velocity of 12.5 ms accelerates uniformly 2 ms until it reaches a speed
-1
of 20 ms then stopped with a uniform decelaration. If the total time taken is 12 seconds. Calculate
the total distance traveled.
Solution.

Let the distance during acceleration is s1 and s2 is a during decelaration. Then;

total distance traveled, = +

1
2
65