Page 75 - eEISBN FINALIZE
P. 75
-2
-1
-1
During uniform acceleration: u = 12.5 ms , a = 2 ms , v = 20 ms .
Hence;
2
2
= + 2
1
2
− 2
=
1
2
2
(20) − (12.5) 2
=
1
2(2)
= .
1
-1
During uniform decelaration: u = 20 ms , v = 0.
Let the the time taken when accelerating is t1, then;
= +
1
−
=
1
20 − 12.5
=
1
2
= .
1
Known, = + then;
2
1
= +
1
2
= 12 − 3.75
2
= .
2
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