Page 64 - ebook fluid mechanics_finalize

FLUID MECHANICS

Weight of pontoon =weight of fluid displaced,

W =   g V which V = Volume

So, W =   g B l D

a) In fresh water,  = 1000 kg / m and D = 1.5 m ;
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Weight of pontoon,

W = 1000  9 . 81  6  12  1 . 5 N

W = 1059 5 . kN

b) In the sea water,  = 1025 kg / m ; therefore,
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Draught in sea water,

W
D =
  g  B  l

= 1059 5 .  10 3 = 1 . 46 m
1025  . 9 81  6  12

c) For maximum draught of 2 m in fresh water,

Total uptrust = weight of water displaced

=  x g  B  l  D =1000  9 . 81 6 12  2 N = 1412 6 . kN

Load which can be supported = Upthrust – weight of pontoon

= 1412 . 6 − 1059 . 5 = 353 . 1 kN

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