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FLUID MECHANICS


                Example 3.6


                       Consider a barge filled with rock.  The barge is 7 m wide, 17 m long, and 2.5 m deep.  If the

                       barge and rock weigh 2 MN, determine the depth of submergence of the barge in water
                       as shown in the figure below.


                                                                   Rock


                                                                                Barge


                                       2.5 m
                                                                                  d
                                                          17 m


                                                                       Submergence Depth

                                                                               3
                                                                3
                       The specific weight of water is 9,810 N/m  (or 9.81 kN/m ).  From the buoyancy concept,
                       the volume of displaced fluid (water) must balance the weight of the barge.  Thus,



                            Wbarge= ρwater X gX Vbarge

                       Substituting volume, Vbarge=  B  x l  x  d  we have:



                       W barg e  =  water   g B l D



                       Wbarge=  (1000 x 9.81)(7 m)(17 m) d    Or


                                   W
                       d =           b arg e
                           (9810 N / m 3 )( m 177  )(  m )



                                     Substituting the weight of the barge gives:


                                                    2 MN
                                     d =                              =  . 1  71 m
                                          ( 8.9  x10 3 N / m 3 )( m 177  )(  m )


















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