Page 25 - KAJIDAYA BAHAN

KAJIDAYA BAHAN

Penyelesaian
i) Tegasan
P
 = --------
A
π D 2
A = -----------
4
-3 2
π (12 x 10 )
= ------------------
4
-4
2
= 1.1309x 10 m

P
 = -------
A

20 x 10 3
= --------------------
-4
1.1309x 10

2
= 176.83 MN/m @ MPa

ii) Terikan sisi
-(Do –Df )
sisi = ------------

Do
-3
-3
-(11.996 x 10 ) –(12 x 10 )
= -------------------------------------
11.996 x 10 -3

-4
= 3.3344 x 10

iii) Terikan paksi

Lf –Lo
paksi = -----------
Lo

0.0435 x 10 -3
= ----------------
-3
50 x 10

-4
= 8.7 x 10

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