Page 30 - KAJIDAYA BAHAN

KAJIDAYA BAHAN

L = Lf –L0

= 152.5 -150

-3
= 2.5 x 10 m

LAE
P = -------
L
-3
-3
9
(2.5 x 10 ) (1.963 x10 )( 110 x 10 )
= --------------------------------------------------
(150 x 10 )
-3

= 3.59 MN

ii) Tegasan
P
 = -------
A
3.59 x 10 6
= ------------------
-3
1.963 x 10

2
= 1.83 GN/m @ GPa

iii) Terikan paksi

Lf –Lo
paksi = -----------
Lo

2.5 x 10 -3
= ----------------
-3
150 x 10

= 0.0167

iv) Tenaga Terikan

1
U = --- PL
2
1
-3
6
= ---- (3.59 x 10 ) ( 2.5 x 10 )
2

= 4.49 J
21