Page 32 - KAJIDAYA BAHAN

KAJIDAYA BAHAN

b) Terikan Paksi


E = -------
paksi


paksi = -------
E

79.57 x 10 6
= ---------------------
9
200 X 10

= 3.9785 x 10 -4

c) Tenaga Terikan

L
paksi = -----------
Lo

L = paksi Lo

-4
= 3.9785 x 10 (2)

-4
= 7.957 x 10

1
U = --- PL
2
1
3
-4
= ---- (400 x 10 ) (7.957 x 10 )
2

= 159.14 J

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