Page 131 - DJJ20063- Thermodynamics 1
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DJJ20063- Thermodynamics 1



                      c)      Nozzle

                              A nozzle utilises a pressure drop to produce an increase in the kinetic energy of

                              the fluid.













                                                   Figure 3.2.7-3 Nozzle


                              The steady flow energy equation gives



                                                           C  2  −C 2           
                                                         +
                                     Q  −W  = m   (h 2  − h 1 )   2  1     ( + gZ 2  − gZ 1  )
                                                                                   
                                                           
                                                              2                 
                                                                                   
                                                
                              Points to note :
                              i.     The  average  velocity  of  flow  through  a  nozzle  is  high,  hence  the  fluid

                                     spends only a short time in the nozzle. For this reason, it may be assumed

                                     that there is insufficient time for heat energy to flow into or out of the fluid
                                     during its passage through the nozzle, i.e. Q = 0.

                              ii.    Since a nozzle has no moving parts, no work energy will be transferred to

                                     or from the fluid as it passes through the nozzle,           i.e. W = 0.
                              iii.   Potential energy is generally small enough to be neglected.



                              Hence the equation becomes

                                                      C  2  −C 2   
                                                    +
                                     0 = m   ( − hh  )    2  1   
                                                               
                                             2   1      2       
                                           






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