Page 55 - eEISBN FINALIZE

JOINT A

2550
FAB

30 0
0

FAD

 F =  F 
y
y
F AB sin 30 + 2250 = 0
F AB sin 30 = -2250
- 2250
F =
AB
sin 30
= - 4500N (C)

→ 
 F =  F x
x
F AB kos 30 + F AD = 0
F AD - = F AB kos 30
= ( 4500 )
- -
= 4500N (T)

JOINT

A = 457 . 14
y

FBC

60
FDC

2250

46