Page 56 - eEISBN FINALIZE
P. 56

→       
                    F =  F x
                      x
                   2250 =  F BC   sin   60

                                 2250
                                  F BC  =
                                sin  60
                                        =  2598 . 08    N    (C)



                    F =   F 
                      y
                             y
                   F BC   kos   60 =  F DC
                               F    DC       = 2598.08   kos   60
                                      = 1299 . 04    N (T)





                 JOINT D



                                            FDB




                    FAD
                                                                 FDC



                                            3000




















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