Page 94 - eEISBN FINALIZE
P. 94

iv.        =         
                                 = 2.5    5.06

                                 =     .                 (  )




               Example 2

                                                        o
               A force of 7.4 kN acting at an angle of  60  to the horizontal on the body. The horizontal distance
               traveled by a body that is 50 m. Calculate the work done.



               Solution:

                                      Fsin 

                                              F

                                                   Fkos

                                  



                                              s


                  = 7.4  10 ,    = 60 ,      = 50  
                                       
                           3

                  =         
                  =                
                  = 7.4  10       60     50
                            3
                                     
                  =                         (  )
                  =            














                                                             85
   89   90   91   92   93   94   95   96   97   98   99