Page 101 - ebook fluid mechanics_finalize

FLUID MECHANICS

v  A 2  p − p
2

1  1 − 1 = 1 2
2g  A 2 2  

So,

 p − p 
2g  1 2 
v =   
1
 A 2 
 1 −1 
 2 
 A 2 

But,

p − p A 2
H = 1 2 ; m = 1
 A 2 2

2gH
So, v =
1
(m 2 − ) 1

To determine the actual discharge, Qactual ;

Q actual = C  A  v
1
1
d
So,

2gH
Q actual = C d  A 1
(m 2 − ) 1

Where Cd = coefficient of discharge.

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