Page 96 - ebook fluid mechanics_finalize
P. 96

FLUID MECHANICS


                              This equation can therefore be written,





                                                      p −  p 2  =  v 2 2  −  v 1 2
                                                       1
                                                                  2 g



                              For continuity of flow,


                                                          A 1 v =  A 2 v
                                                                    2
                                                             1
                              or


                                                       d 
                                                        2       d   2  
                                                        1   v =   2  v 
                                                            1         2
                                                       4        4   

                              then,


                                                                   2
                                                         2
                                                       d   v =  d   v
                                                             1
                                                        1
                                                                  2
                                                                       2
                              So,
                                                                   d   2
                                                                  
                                                               v  2 = v 1   1  
                                                                      
                                                                   d 2 




                              Putting v =   5 . 4  m  s / ,  d = 10 mm,  d =  7 mm
                                       1             1            2





                                                           10  2
                                                   v 2  =  5 . 4      9=  . 18 m  s /
                                                            7 


                              and


                                                      p −  p 2  =  v 2 2  −  v 1 2
                                                       1
                                                                  2 g










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