Page 97 - ebook fluid mechanics_finalize

FLUID MECHANICS

p 1 − p 2 = . 9 18 − 5 . 4 2 3= . 26m
2
2
 2 . 9 81

p − p
2
1 2 3= . 26m


p − p = 26.3 m 2  
1
2

2
3
Pressure difference, p − p = . 3 26 . 9 81 10 N / m
2
1
31= 9 . kN / m
3

 d 2
3
Area of piston = kN / m
4

 ( 020.0 ) 2
2
= = . 0 000314 m
4

We all know that,

Force, F = p A

And,

p = pressure and A = area

The force, F:

3
Force on piston = 31  10  . 0 000314 = 10 1 . N
9 .

86