Page 51 - ebook fluid mechanics_finalize
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FLUID MECHANICS


                Example 1





















                       A U tube manometer measures the pressure difference between two points A and B in a

                       liquid. The U tube contains mercury. Calculate the difference in pressure if h = 2.0 m, h2 =
                       0.35 m and h1 = 0.5 m. The liquid at A and B is oil  ( s = 0.85 ) and the specific gravity of

                       mercury is 13.6.


                       Solution :


                       Since C and D are at the same level in the same liquid at rest


                       Pressure  p at C = Pressure  p  at D
                                  C
                                                    D

                       For the left hand limb,      p =   p +  oil  h
                                                           A
                                                     C
                       For the right hand limb,           p =  p +  oil h +  hg h
                                                           B
                                                                   2
                                                      D
                                                                           1
                       Since,       p =  p D
                                  C

                                p +    h =  p +    h +    h
                                         A  oil  B  oil  2  hg  1

                       Pressure difference,     p −  p
                                              A
                                                   B

                                            p −  p =   h +   h −   h
                                      B
                                                        hg
                                 A
                                                            1
                                                 2
                                            oil
                                                                  oil
                          =   . 0  85 (9810 )( 35.0  ) 13+  6 .  (9810 )( ) 05.0  −  . 85 (9810 )( 0.2  )

                              52949=  . 47 N / m =  52 . 949 kN  / m
                                           2
                                                             2







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