Page 47 - ebook fluid mechanics_finalize
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FLUID MECHANICS


                Example 1


                       A U-tube manometer similar to that shown below is used to measure the gauge pressure

                                                              3
                                                                                                      3
                                                                                                              3
                       of water (mass density ρ = 1000 kg /m ). If the density of mercury is 13.6 × 10  kg /m ,
                       calculate the gauge pressure at A if  h1 = 0.45 m and  h2 = 0.7 m above BC.



















                       Solution :


                                                    3
                                                                                  3
                                                           3
                                                                           3
                       Considering    hg  = 13  6 .  10 kg / m ,   W  =  0 . 1  10 kg  / m , h =  . 0  45  m h =  7 . 0  m
                                                                                                ,
                                                                                                    2
                                                                                      1
                       the pressure at left-hand limb;
                       p =  Pressure,  p  at A + Pressure due to depth,  h of water
                                        A
                                                                        1
                         B
                                 =   p +   W  h
                                         1
                                A
                                =  p +   W  gh
                               A
                                         1

                       the pressure at right-hand limb;


                        p =  Pressure p  at D + Pressure due to depth h of mercury
                         C
                                                                        2
                                        D
                        p  =  0 +  hg h  = 0 +   hg  gh
                         C
                                      2
                                                    2
                       Since       p =  p …………… p +    W gh =   hg  gh
                                      C
                                 B
                                                                    2
                                                           1
                                                  A
                              p =    Hg gh −   w gh   13 =  6 .  10   . 9 81  7 . 0 −  0 . 1  10   . 9 81  . 0  45
                                                                                   3
                                                              3
                                                  1
                                A
                                          2
                                              2
                                                           3
                                                                  2
                              = 88976  7 . N  / m = 88 . 97  10 N  / m



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