Page 46 - ebook fluid mechanics_finalize
P. 46

FLUID MECHANICS


















                       p =  Pressure p  at D + Pressure due to depth   h of liquid (mercury)
                                                                       2
                         C
                                       D
                But      p = Atmospheric pressure   OR   Zero gauge pressure
                        D

                                                        +
                       And so,         p  =  0 +  hg h   =  0  hg gh 2
                                    C
                                                 2

                       Since   p =  p
                                      C
                               B


                               p +       gh =         gh
                                                           2
                                                     hg
                                 A
                                        W
                                              1
                       so,
                                               p =         gh −         gh  1
                                                         hg
                                                                        w
                                                 A
                                                                2










































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