Page 107 - DJJ20063- Thermodynamics 1
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DJJ20063- Thermodynamics 1






                                            Feedback To Activity 3B




                      3.4    Since the gas is compressed according to the law pV  = C, then,
                                                                                1.4


                                     p 1 V 1  4 . 1  =  p 2 V 2  4 . 1


                                      p    V    4 . 1  V   p    4 . 1 / 1
                                      1  =    2      or    2  =    1  
                                                            
                                                                
                                      p 2   V 1      V 1    p 2 

                              from which,


                                             p    4 . 1 / 1  p
                                                
                                     V 2  = V 1    1    = V  4 . 1  1
                                              p 2     1   p 2



                                                   138
                                          = 0.012 x   4 . 1
                                                    690
                                                  3
                                          = 0.0348 m




                      3.5    The work done during a polytropic expansion is given by the expression:

                                   p  V  − p  V
                              W  =   1  1   2  2     [larger pV- small pV]
                                       n  − 1
                              In this problem V2 is, as yet, unknown and must therefore be calculated.

                              Now

                                              n
                                      n
                                   p
                                       V =  p 2 V
                                             2
                                    1
                                      1
                                              p   n / 1
                                                 
                                    V =  V   1  
                                           1 
                                       2
                                              p 2 
                                                   2070   . 1 / 1  35
                              or     V2 = 0.014 x     
                                                   207 
                                                 3
                                     V2 = 0.077 m
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