Page 97 - DJJ20063- Thermodynamics 1

DJJ20063- Thermodynamics 1

Feedback to Activity 3A

3.1 Data: m = 1.0 kg; T1= 527 + 273 = 800 K

p1 = 20 bar; p2= 1.4 bar; V2 = ?

Carbon dioxide is a perfect gas and we can apply the following characteristic gas

equation at state 1.

p1V1 = mRT1
mRT 1
V1 =
p 1

1x 189x 800
=
20x 10 5
3
= 0.0756 m
Applying the general property relation between state 1 and 2

p V p V
1 1 = 2 2
T 1 T 2

For an isothermal process T1 = T2

Hence,
p V = p V
1 1 2 2
20
V2 = x . 0 0756
4 . 1

3
V2 = 1.08 m

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