Page 81 - KAJIDAYA BAHAN

KAJIDAYA BAHAN

b) Jumlah momen luas kedua sekitar paksi neutral.

IPN = IPN 1 + IPN 2

3
3
bd + Ah 2 bd + Ah 2
= -------------- + --------------
12 1 12 2

3
3
120(80) + 9600( 40-33.18) 2 60(50) + 3000(55-33.18) 2
= ----------------------------------- + -----------------------------------
12 1 12 2

6
= 3.513 x 10 mm 4

4
-6
= 3.513 x 10 m

c) Panjang rasuk.

WL 2
Mmax = ---------
2

Mmax ( 2)
L = ---------------
W

3
(750 x 10 ) ( 2 )
= -------------------
15 x 10 3

= 10 m

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