Page 49 - DJJ20063- Thermodynamics 1

DJJ20063- Thermodynamics 1

o
So, at 100 bar and 425 C, we have
3
-2
v = 2.812 x 10 m /kg
h = 3172 kJ/kg

 From equation 2.8,
u = h – Pv

2
-2
3
2
= 3172 kJ/kg – (100 x 10 kN/m )(2.812 x 10 m /kg)
= 2890.8 kJ/kg

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