Page 54 - DJJ20063- Thermodynamics 1
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DJJ20063- Thermodynamics 1
Example 2.7
Determine the specific enthalpy of dry saturated steam at 103 bar.
Solution to Example 2.7
h − 2725 2715 − 2725
P g =
103 −100 105 −100
105
103 3 (−10 )
h = + 2725
g
100 5
hg
2725 hg 2715 h = 2719 kJ/kg
g
Example 2.8
o
Determine the specific volume of steam at 8 bar and 220 C.
Solution to Example 2.8
o
From the Steam Tables at 8 bar, the saturated temperature (ts) is 170.4 C.
o
The steam is at superheated condition as the temperature of the steam is 220 C > ts.
An extract from the Steam Tables,
p / (bar) t 200 220 250
o
o
(ts / C) ( C)
8 v 0.2610 v 0.2933
(170.4)
P
.
.
.
250 v − 0 2610 = 0 2933 − 0 2610
220 − 200 250 − 200
220
200
3
v = 0 27392. m /kg
v
0.2610 v 0.2933
45 | P a g e
