Page 51 - DJJ20063- Thermodynamics 1
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DJJ20063- Thermodynamics 1
Feedback to Activity 2C
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2.6 From the superheated table at 120 bar, the saturation temperature is 324.6 C.
Therefore, the steam is superheated.
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o
Degree of superheat = 500 C – 324.6 C
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= 175.4 C
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So, at 120 bar and 500 C, we have
-2
3
v = 2.677 x 10 m /kg
h = 3348 kJ/kg
From equation 8.6,
u = h – Pv
-2
3
2
2
= 3348 kJ/kg – (120 x 10 kN/m )(2.677 x 10 m /kg)
= 3026.76 kJ/kg
2.7 At 160 bar, hg = 2582 kJ/kg. This is less than the actual specific enthalpy of
3139 kJ/kg. Hence, the steam is superheated.
From the superheated table at 160 bar, the specific enthalpy of 3139 kJ/kg is located at a
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temperature of 450 C.
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The degree of superheat = 450 C – 347.3 C
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= 102.7 C
3
-2
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At 160 bar and 450 C, we have v = 1.702 x 10 m /kg
From equation 2.6,
u = h – Pv
3
2
2
-2
= 3139 kJ/kg – (160 x 10 kN/m )(1.702 x 10 m /kg)
= 2866.68 kJ/kg
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