DJJ20063- Thermodynamics 1
At constant volume process,
Initial specific volume = final specific volume
v1 = v2
x1vg1 at 2.25 bar = x2vg2 at 1.8 bar
1(0.7935) = x2 (0.9774)
. 0 ( 1 7935 )
x =
2
. 0 9774
P
= 0.81
bar
1 v1 = v2
2.25
1.80 2
3
v m /kg
0.7935 0.9774
49 | P a g e