Page 60 - DJJ20063- Thermodynamics 1

DJJ20063- Thermodynamics 1

Feedback to Activity 2D

2.8
T
h − 2925 3039 − 2925
=
300 275 − 250 300 − 250
275

h
250 = 2982 kJ/kg

h
2925 h 3039

o
o
2.9 Degree of superheat = 380 C – 179.9 C
o
= 200.1 C

T

400
s − . 7 301 . 7 464 − . 7 301
380 =
380 − 350 400 − 350
350

s
s = . 7 3988 kJ/kg K
7.301 s 7.46

4

2.10 An extract from the superheated steam table:

o
t( C) 600 650 700
p(bar)
-2
120 3.159 x 10 -2 v1 3.605 x 10

125 v
-2
-2
130 2.901 x 10 v2 3.318 x 10

o
Firstly, find the specific volume (v1) at 120 bar and 650 C;
51 | P a g e